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  • BMAT 2020 Section 2 Q9

  • Nicolas Sanchez

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    June 26, 2021 at 7:23 am
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    Some rabbits have a genetic condition. The dominant allele codes for this condition.
    A homozygous dominant rabbit mated with a rabbit that did not have the condition.
    They had three offspring.
    One of the offspring then mated with a rabbit that did not have the condition and they also produced three offspring. Two of the offspring had the condition and one did not.
    One body cell that is in early interphase is taken from each of the rabbits in these three generations.
    What is the total number of copies of the allele for the condition in this collection of cells?

    A. 6
    B. 7
    C. 8
    D. 11
    E. 12
    F. 14

    Mehrnaz Abootorabi voted up
  • Paris Pitsinikos

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    July 21, 2021 at 6:26 pm
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    We are looking for the dominant allele in the family tree. I have done the crosses and written the family tree. Doing them yourself should result in the same genotypes. Be sure to be carefully while reading the question as well cause it is tricky. The total amount of ‘A’ is 7.

    The answer is B.

    Mehrnaz Abootorabi voted up
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